This is in the third quadrant where the tangent of the angle is positive
tan pi/4 = 1 = y/-1 so y = -1
The required point is (-1,-1)
Answer:
x = 9
Step-by-step explanation:
2x - 3 = 15
2x = 15 + 3
2x = 18 (divide both sides by 2 to get x)
2x/2 = 18/2
x = 9
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
Answer:
X
2
Step-by-step explanation:
