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SCORPION-xisa [38]
3 years ago
10

Explain how to use properties to prove d + (8d + 1) + 7 is equivalent to 8 + 9d.

Mathematics
2 answers:
meriva3 years ago
8 0

Answer:

Use the associative property to move the parentheses, and the expression becomes (d + 8d) + 1 + 7. Combine like terms, and the expression becomes 9d +8. Use the commutative property to change the order of the terms, and the expression becomes 8 + 9d.

Step-by-step explanation:

vekshin13 years ago
6 0

Answer:

Exact response: Use the associative property to move the parentheses, and the expression becomes (d + 8d) + 1 + 7. Combine like terms, and the expression becomes 9d +8. Use the commutative property to change the order of the terms, and the expression becomes 8 + 9d.

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A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the prob
UkoKoshka [18]

Answer:

The probability that 8 mice are​ required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are​ required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

P(X=r)=^nC_r p^rq^{n-r}

Where, p is the probability of success p=\frac{2}{7}

q is the probability of failure q=1-p, q=1-\frac{2}{7}=\frac{5}{7}

n is total number of trials n=8

r=3

Substitute the values,

P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}

P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}

P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}

P(X=3)=0.2428

Therefore, the probability that 8 mice are​ required is 0.2428.

5 0
4 years ago
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Basile [38]

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Step-by-step explanation:

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x^{2} -x

x (x - 1)

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