Answer:
Y' = 360ex+ 30e
Step-by-step explanation:
Y=e×6x×(6x+1) × 5
y'= d/dx (e×6x ×(6x+1)×5)
y'=d/dx(30ex ×(6x+1))
y'=d/dx(180ex^2 + 30ex)
y'=d/dx(180ex^2) + d/dx (30ex)
Calculate the derivative
y'=180e×2x +30e
y'=360ex+30e
Is %
=
of 100
x 6
=
550 100
cross multiply and divide
100x=3300
divide both sides by 100
x=33
Answer:
y = x² - 8x + 17
Step-by-step explanation:
Recall this formula:
y = a(x-h)² + k
Original equation was y = x², which in this form looks like
y = 1(x - 0)² + 0
If the shape of the graph didn't change, that means that a (the compressor/intensifier) stayed the same (a - value) meaning we can write the equation as..
y = (x-h)² + k
Remember, (h, k) is the vertex, which looking from your graph is at (4, 1)
y = (x - 4)² + 1
y = x^2- 8x + 16+1
y = x² - 8x + 17
I am not sure on how to do this however here is a link with information thst will be able to help you around this subject.i hope this helps
https://www.bbc.com/bitesize/guides/z8k887h/revision/1
