length times width times height
(1¼) (4) (2)
= 10 cm3
Answer:
<em>Sorry, If this late but here's the answer. The data plots represent the hours students study each week in two different classrooms. The mean number of hours a student in Mr. Hart’s class studies is </em><em>4.6</em><em> hours. The mean number of hours a student in Ms. Perry’s class studies is </em><em>2.8</em><em> hours. A typical student in Mr. Hart’s class studies </em><em>More than</em><em> a typical student in Ms. Perry’s class. </em><em>Good Luck!</em>

<em>Here's the photo... </em>
Answer:
the answer is the first -5cd
Answer:
The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).
Critical value t=1.318
Step-by-step explanation:
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=0.165.
The sample size is N=25.
When σ is not known, s divided by the square root of N is used as an estimate of σM:

The degrees of freedom for this sample size are:

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).