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GarryVolchara [31]
3 years ago
15

A farmer is going to divide her 30 acre farm between two crops. Seed for corn costs $15 per acre. Seed for wheat costs $30 per a

cre. The farmer can spend at most $750 on seed.If wheat brings in a profit of $110 per acre, and corn brings in a profit of $100 per acre, how many acres of each crop should the farmer plant to maximize her profit
Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

$3200

Step-by-step explanation:

The total area of land is 30 acre. Let x represent the area in acre that corn is planted and y represent the area in acre that wheat is planted. Therefore:

x + y = 30               (1)

Also, the farmer can spend at most $750 on seeds. Corn cost $15 per acre, maize cost $30 per acre. Hence:

15x + 30y ≤ 750      (2)

Also, x and y > 0

The profit is given by the function:

Profit = 100x + 110y

Graphing equation 1 and equation 2 and solving, we get the points:

(10, 20)

Hence the maximum profit is at:

Max profit = 100(10) + 110(20) = $3200

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Tanya has several bills in her wallet. She has a total of $40. If she has one more $5 bill than $10 bills, and two more $1 bills
mars1129 [50]

Answer:

no. of $10 bill =2

no. of $5 bill = 3

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Step-by-step explanation:

Let the no. of $10 bill be x

Total value of $10 bill = $10*no. of $10 bill = $10x

Given that

Tanya has one more $5 bill than $10 bills

Thus, no. of $5 bill = x+1

Total value of $5 bill = $5*no. of $5 bill = $5(x+1)

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she has two more $1 bills than $5 bills

no. of $1 bill = no. of $2 bill + 2 = x+1+2 = x+3

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= 10x + 5(x+1) + 1(x+3)

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no. of $10 bill = x = 2

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