The Answer would be B
it would be B because 8-2 is 6 and if you keep subtracting by 6 you will get ur answer and to get the first one you would just need to add 8 plus 6 to get 14
9514 1404 393
Answer:
y -2 = -2/3(x +4)
Step-by-step explanation:
There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.
That form is ...
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
__
The two marked points are (-4, 2) and (5, -4). All we need is the slope.
The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)
m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3
Using the first point, the equation for the line can now be written as ...
y -2 = -2/3(x -(-4))
y -2 = -2/3(x +4)
The indicated sum for the geometric series is 121.5
<h3>How to identify the indicated sum for the
geometric series?</h3>
The series is given as:
162 − 54 + 18 − 6 + .....
Start by calculating the common ratio of the geometric series.
This is calculated using
r = -54/162
Evaluate
r = -1/3
The indicated sum for the geometric series is then calculated as:
S = a(1 - r^n)/1 - r
Substitute the known values in the above equation
S = 162(1 - (-1/3)^7)/1 + 1/3
Evaluate the exponent and the sum
S = 162(1 + 1/2187)/4/3
Evaluate the sum
S = 162(2188/2187)/4/3
Express as products
S = 162 * (2188/2187)* 3/4
Evaluate the product
S = 162 * 547/729
Evaluate the product
S = 121.5
Hence, the indicated sum for the geometric series is 121.5
Read more about geometric series at
brainly.com/question/24643676
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All your doing here is 37-19 adding negative is the same has munising
So 37-19=18
Answer:
The correct option is c.
discrete data set because there are a finite number of possible values.
Step-by-step explanation:
A discrete data set are data set that can be counted , they are not represented in intervals.