Answer:
67 square units
Step-by-step explanation:
The area using the left-hand sum is the sum of products of the function value at the left side of the interval and the width of the interval.
<h3>Area</h3>
The attachment shows a table of the x-value at the left side of each interval, and the corresponding function value there. The interval width is 1 unit in every case, so the desired area is simply the sum of the function values.
The approximate area is 67 square units.
Answer:
CAB = CAD + DAB
161 = (5X + 7) + (3X - 6)
161 = 8X + 1
160 = 8X
160/8 = 8X/8
X = 20
Solve for x:
x^2 + 10 x + 12 = 36
36 = 36:
x^2 + 10 x + 12 = 36
Subtract 12 from both sides:
x^2 + 10 x = 24
Add 25 to both sides:
x^2 + 10 x + 25 = 49
Write the left hand side as a square:
(x + 5)^2 = 49
Take the square root of both sides:
x + 5 = 7 or x + 5 = -7
Subtract 5 from both sides:
x = 2 or x + 5 = -7
Subtract 5 from both sides:
Answer: x = 2 or x = -12 Thus the Answer is A.