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3 years ago

6

The area of John’s rectangular lawn and cement border is 1222 square feet. If the cement border is 2 feet wide, and the length o

f his lawn is 27 feet less than 3 times the width, what are the dimensions of John’s lawn?

2 answers:

Juliette [100K]3 years ago

3 0

Answer:

idk good luck with that one :)

Step-by-step explanation:

ravindu3 years ago

0 0

W=22.84 or W=-19.18

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Expand the following 1/6 (18x-24)

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So, it would be:
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Find an equation for the line that passes through the points (5.-5) and (-4,-2)

ANEK [815]

Answer:

$\large\boxed{y=-\dfrac{1}{3}x-\dfrac{10}{3}\to x+3y=-10}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (5, -5) and (-4, -2).

Substiute:

$m=\dfrac{-2-(-5)}{-4-5}=\dfrac{-2+5}{-9}=\dfrac{3}{-9}=-\dfrac{1}{3}$

Put the value of the slope and the coordinates of the point (5, -5) to the equation of a line:

$-5=-\dfrac{1}{3}(5)+b$

$-5=-\dfrac{5}{3}+b$ <em>add 5/3 to both sides</em>

$-\dfrac{15}{3}+\dfrac{5}{3}=b\\\\-\dfrac{10}{3}=b\to b=-\dfrac{10}{3}$

Finally we have the equation of a line in the slope-intercept form:

$y=-\dfrac{1}{3}x-\dfrac{10}{3}$

Convert to the standard form <em>(Ax + By = C)</em>:

$y=-\dfrac{1}{3}x-\dfrac{10}{3}$ <em>multiply both sides by 3</em>

$3y=-x-10$ <em>add x to both sides</em>

$x+3y=-10$

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3 years ago