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Gekata [30.6K]
2 years ago
10

R-C=P solve for C Has to Be all capitals and be in that order

Mathematics
1 answer:
Kay [80]2 years ago
6 0

Answer:

Step-by-step explanation:

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Please help me ive gotten 2 wrong pelase help me please
Tju [1.3M]
The blue one with four corners!!!
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3 years ago
AB and CD are parallel find the value of y<br> Show clearly how you got your answers with reasons
Zina [86]

Answer:

y = 167°

Step-by-step explanation:

The vertex of the triangle = 154° ( alternate angle to 154° )

The triangle has 2 equal legs so is isosceles with 2 base angles congruent

base angle = \frac{180-154}{2} = \frac{26}{2} = 13°

base angle and y are adjacent angles, lie on straight line AB and sum to 180°

y + 13° = 180° ( subtract 13° from both sides )

y = 167°

5 0
2 years ago
Help please n ty :P<br> sdhgfahedgewkgfzndb
Ugo [173]

Answer:

y=-3.2\\\\y=-2.2\\\\y=-1.8

Step-by-step explanation:

Insert the given x values for the given equation to find the corresponding y coordinate:

y=0.2x-2

x:-6,-1,1

Insert -6:

y=0.2(-6)-2

Simplify multiplication (when multiplying a negative and a positive, the result will always be negative):

y=-1.2-2

Simplify (when subtracting from a negative number, add the values, but keep the negative symbol):

y=-3.2

Insert -1:

y=0.2(-1)-2\\\\y=-0.2-2\\\\y=-2.2

Insert 1:

y=0.2(1)-2\\\\y=0.2-2\\\\y=-1.8

:Done

3 0
3 years ago
2 Points<br> Which of the following is(are) the solution(s) to . x+6 = 2x - 1?
seropon [69]

Answer:

x = 7

Step by step explanation:

<em>minus</em><em> </em><em>x</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>

6 = x -1

<em>add</em><em> </em><em>1</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>

<em>x</em><em> </em><em>=</em><em> </em><em>7</em>

7 0
3 years ago
How do you solve f(x) = x2 + x - 20?​
Darina [25.2K]

\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + 5x - 4x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x(x + 5) - 4(x + 5)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(x + 5)(x -  4)

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x =  - 5 \:  \: and \:  \: 4

4 0
2 years ago
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