Step-by-step explanation:
120 ÷ 1.6 = 75.
so 75 miles per hour.
75 × 2 = 150
therefore 150 miles in 2 hours
Answer:
Step-by-step explanation:
Let's look at the first two, and hopefully you'll be able to figure the rest out:
1. Answer below
![d = rt](https://tex.z-dn.net/?f=d%20%3D%20rt)
The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to divide both sides of the equation by
:
![\frac{d}{t} = \frac{rt}{t}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bt%7D%20%3D%20%5Cfrac%7Brt%7D%7Bt%7D)
![\frac{d}{t} = r](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bt%7D%20%3D%20r)
2. Answer below
![B = T - Lc](https://tex.z-dn.net/?f=B%20%3D%20T%20-%20Lc)
The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to add
to both sides of equation:
![B + Lc = T - Lc + Lc](https://tex.z-dn.net/?f=B%20%2B%20Lc%20%3D%20T%20-%20Lc%20%2B%20Lc)
![B + Lc = T](https://tex.z-dn.net/?f=B%20%2B%20Lc%20%3D%20T)
D is the correct answer to this question
Answer:
The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
Step-by-step explanation:
In a random sample of 300 boards the number of boards that fall outside the specification is 12.
Compute the sample proportion of boards that fall outside the specification in this sample as follows:
![\hat p =\frac{12}{300}=0.04](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%5Cfrac%7B12%7D%7B300%7D%3D0.04)
The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:
![CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
The critical value of <em>z</em> for 95% confidence level is,
![z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3Dz_%7B0.05%2F2%7D%3Dz_%7B0.025%7D%3D1.96)
*Use a <em>z</em>-table.
Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:
![CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C%3D0.04%5Cpm1.96%5Csqrt%7B%5Cfrac%7B0.04%281-0.04%29%7D%7B300%7D%7D%5C%5C%3D0.04%5Cpm0.022%5C%5C%3D%280.018%2C%200.062%29%5C%5C%5Capprox%281.8%5C%25%2C%206.2%5C%25%29)
Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
(x-4)•2 < 9
the difference between x and 4 means to subtract
and twice that means to double or times by 2
and all that’s LESS than 9
so the sign opens up towards the 9