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VLD [36.1K]
4 years ago
10

In which section of the graph does the actual solution to the system lie?

Mathematics
1 answer:
r-ruslan [8.4K]4 years ago
3 0

Answer: the middle

Step-by-step explanation:

dd

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Which shows the pre-image od quadrilateral w'x'y'z' before the figure was rotated according to the rule (x,y) -> (-x,-y)?
JulsSmile [24]

Answer:

The pre-image of the quadrilateral is attached.

Step-by-step explanation:

Each point (x, y) is rotated with the rule (x, y) -> (-x, -y).

So, point W'(2, 3) was W(-2, -3) before rotation.

X'(6, 3) was X(-6, -3)

Y'(6, 4) was Y(-6, -4).

Z'(3, 5) was Z(-3, -5).

The pre-image of the quadrilateral is attached.


4 0
4 years ago
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How does the number line represent equivalent fractions and decimals?
icang [17]
Once you get to 0 that is the decimal
5 0
3 years ago
Please help!! It’s for homework.
motikmotik

Answer:

t = cost of a ticket

4t+55

Step-by-step explanation:

Cost 1

4 airline tickets

Let t = cost of a ticket

4*t

Cost 2

extra baggage fee

55

Add the costs together

4t+55

8 0
4 years ago
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EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
4 years ago
⅔ x 6/7 ÷ 8/14 help please​
ahrayia [7]

Answer:

1

Step-by-step explanation:

\frac{2}{3} *\frac{6}{7} ÷ \frac{8}{14}

= \frac{2}{3} *\frac{6}{7} *\frac{14}{8}

=\frac{2}{3} *\frac{6}{7} *\frac{7}{4}

=\frac{2*6*7}{3*7*4}

=\frac{84}{84}

=1

8 0
3 years ago
Read 2 more answers
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