Answer:
Part 1) The area of the shaded region is
Part 2) The area of the shaded region is
Step-by-step explanation:
Part 1) Figure N 1
I assume that the figure ABCD is a square
we know that
The area of the shaded region is equal to the area of the square ABCD minus the area of semicircle BC plus the area of semicircle AD
therefore
The area of the shaded region is equal to the area of the square ABCD
The area of the square is
Part 2) Figure N 2
I assume that the triangle ABC is a right isosceles triangle
so
AB=BC
AB ⊥ BC
The area of the shaded region is equal to the area of triangle plus the area of semicircle
A) <em>Find the area of the triangle ABC</em>
The area of triangle is
substitute
B) Find the area of semicircle
The area of semicircle is equal to
we have
-----> the radius is half the diameter
substitute
therefore
The area of the figure is equal to
Answer:
250%
Step-by-step explanation:
Hi there!
In order to solve this problem, we have to divide 200 by 80.
When we do this, we get 2.5. The number in the ones spot, in this case 2, would be worth 200%.
Now we have the 0.5
A half is equivalent to 50%, so we add those two percentages together to get 250%.
I hope this helps!
456.29 in the answer there
should be 5 significant figures.
Answer:
The decimal equivalent is approximately .941176.
32/34 = 16/17, but 16/17 is in lowest terms because 17 is a prime.
Step-by-step explanation: