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Eduardwww [97]
3 years ago
6

If (x − 6) is a factor of the polynomial function f(x) = 5x2 − 28x − 12, which of the following is another factor?

Mathematics
2 answers:
Gwar [14]3 years ago
7 0

Answer:

(5x + 2)

may be correct answer!

Aneli [31]3 years ago
6 0

Answer:

(5x + 2)

Step-by-step explanation:

The product of (ax + b) and (cx + d) is:

(ax + b) (cx + d) = ac x² + (ad + bc) x + bd

The leading coefficient is the product of the coefficients of each factor.

The constant is the product of the constants of each factor.

So if (x − 6) is a factor of 5x² − 28x − 12, the other factor must have a coefficient of 5 and a constant of 2.

(5x + 2)

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What is the factor of 5x^2 + 10x
Marat540 [252]

Answer: 5 x 2 − 10 x = 5 x ( x − 2 )

Step-by-step explanation:

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3 years ago
I NEED HELP W THIS QUESTION!!
Kobotan [32]

Answer:

A

Step-by-step explanation:

To find the value you can just find 12% of each number (trial and error), until one of them gives you 90 as an answer:

A) 750

750 *  0.12 = 90

B) 1080

1080 * 0.12 = 129.6

C) 360

360 * 0.12 = 43.2

D) 1168

1168 * 0.12 = 140.16

This tells you that 90 is 12% of the 750, and that is why it is your answer


I hope this helps!

8 0
3 years ago
What is the product?( square root 3x+ square root 5) (square root 15x+ 2 square root 30)
hichkok12 [17]
(\sqrt{3x}+\sqrt5)\cdot(\sqrt{15x}+2\sqrt{30})\\\\=(\sqrt{3x})(\sqrt{15x})+(\sqrt{3x})(2\sqrt{30})+(\sqrt5)(\sqrt{15x})+(\sqrt5)(2\sqrt{30})\\\\=\sqrt{(3x)(15x)}+2\sqrt{(3x)(30)}+\sqrt{(5)(15x)}+2\sqrt{(5)(30)}\\\\=\sqrt{45x^2}+2\sqrt{90x}+\sqrt{75x}+2\sqrt{150}\\\\=\sqrt{9x^2\cdot5}+2\sqrt{9\cdot10x}+\sqrt{25\cdot3x}+2\sqrt{25\cdot6}\\\\=\sqrt{9x^2}\cdot\sqrt5+2\sqrt9\cdot\sqrt{10x}+\sqrt{25}\cdot\sqrt{3x}+2\sqrt{25}\cdot\sqrt6
=3x\sqrt5+2\cdot3\sqrt{10x}+5\sqrt{3x}+2\cdot5\sqrt6\\\\=3x\sqrt5+6\sqrt{10}+5\sqrt{3x}+10\sqrt6
3 0
3 years ago
Read 2 more answers
Bob gets paid 64 hour heard that is 2/3 Melissa makes how much is Alicia paid per hour
Thepotemich [5.8K]

Answer:

64

Step-by-step explanation:

4 0
3 years ago
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