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Norma-Jean [14]
3 years ago
6

Find the equation of the line ER function represented by the table Below in slope intercept form

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

hold on a sec

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The perimeter of a playing field for a certain sport is 174 ft. The field is a rectangle, and the length is 45 ft longer than th
Leno4ka [110]

Answer:

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W)............... Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W............ Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W............. Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

3 0
3 years ago
HELP TIMED BRAINLY POINTS​
kozerog [31]

Answer:

dude you need to show the whole answer

Step-by-step explanation:

sorry I couldn't help

6 0
3 years ago
3(x^2+4x)+4(y^2-2y)=32
nekit [7.7K]

Answer:

3x^2 + 12x + 4y^2 - 8y = 32

Step-by-step explanation:

3(x^2+4x)+4(y^2-2y)=32

At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:

or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32

or, 3x^2 + 12x + 4y^2 - 8y = 32

Since the equation does not have anything to add or deduct, therefore, it is the answer.

5 0
4 years ago
Which statement is true about the polynomial 3x2y2 − 5xy2 − 3x2y2 + 2x2 after it has been fully simplified
Len [333]
The polynomial <span>3x2y2 − 5xy2 − 3x2y2 + 2x2 can be simplified by combining like terms.

The result is:
-5xy2 + 2x2

The polynomial is
a binomial (2 terms),
the degrees is 3
the highest order in x is 2 and the highest order in y is 2.</span>
4 0
3 years ago
You are trying to figure out how many gumballs you need to fill a 7.3 x 5.0 x 9.4 rectangular box for Halloween. Each gumball ha
riadik2000 [5.3K]

According to the calculations made, 410 gumballs will be needed to fill the box.

Since you are trying to figure out how many gumballs you need to fill a 7.3 x 5.0 x 9.4 rectangular box for Halloween, and each gumball has a radius of 1/2 in, if the packing density for spheres is 5/8 of the volume will be filled with gumballs while the rest will be air how many gumballs will be needed, to determine this amount the following calculation must be performed:

  • (Volume of box x 5/8) / volume of gumballs = Amount of gumballs  
  • Volume of a sphere = 4/3 x 3.14 x (radius x radius x radius)  
  • Volume of a gumball = 4/3 x 3.14 x (0.5 x 0.5 x 0.5) = 0.5235 inches  
  • ((7.3 x 5 x 9.4) x 5/8) / 0.523 = X
  • (343.1 x 5/8) / 0.523 = X
  • 214.4375 / 0.523 = X
  • 410 = X

Therefore, 410 gumballs will be needed to fill the box.

Learn more in brainly.com/question/1578538

4 0
3 years ago
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