Answer:
Area of shaded part ABCEF = 66 sq.cm
Step-by-step explanation:
AB = 8cm
CD = 8cm
Let DE = x cm
CE = 3x cm
CD = CE + DE = 8cm
x + 3x = 8
4x = 8
x = 8/4 = 2 cm
DE = 2cm
CE = 3 * 2 = 6 cm
Area of triangle ADE = 1/2 * base * height
= 1/2 * DE * AD
= 1/2 * 2 * 11 = 11 sq. cm
Area of triangle AEF = Area of triangle ADE = 11 sq. cm
Area of Rectangle ABCD = l * b = 8 * 11 = 88 sq.cm
Area of shaded part ABCEF = Area of Rectangle ABCD - (Area of triangle AEF + Area of triangle ADE)
= 88 - ( 11 + 11 ) = 88 -22 = 66 sq.cm
Answer:
first option
Step-by-step explanation:
Given
f(x) =
← factorise the numerator
=
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at (
, 0 )
Thus
discontinuity at (- 4, - 11 ), zero at (
, 0 )
Answer:
The answer would be -4.
Step-by-step explanation:
This is because the product of a number and -3 must be 8 less than 20, which is 12. And -3 times -4 is 12.
Answer:

Step-by-step explanation:

We´ll <u>Apply Difference Two Squares Formula:</u>


<u>Apply exponent rule</u>:


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