En una pension de perros hay tres perros que pesan 20kg 10kg y otro 5kg si se contempla que 70kg de alimento dura 2 meses¿que ca
ntidad de alimento le toca a cada perro ? Problema de proporcionalidad inversa
1 answer:
Answer:
40kg
20kg
10kg
Step-by-step explanation:
The computation of the food each one is getting as follows
Total weights of all dogs
= 20 kg + 10 kg + 5kg
= 35 kg
And, the food is 70 kg
So, each one is getting
for 20 kg
= 70 ÷ 35 × 20
= 40 kg
For 10 kg
= 70 ÷ 35 × 10
= 20 kg
And, for 5 kg
= 70 ÷ 35 × 5
= 10 kg
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