En una pension de perros hay tres perros que pesan 20kg 10kg y otro 5kg si se contempla que 70kg de alimento dura 2 meses¿que ca
ntidad de alimento le toca a cada perro ? Problema de proporcionalidad inversa
1 answer:
Answer:
40kg
20kg
10kg
Step-by-step explanation:
The computation of the food each one is getting as follows
Total weights of all dogs
= 20 kg + 10 kg + 5kg
= 35 kg
And, the food is 70 kg
So, each one is getting
for 20 kg
= 70 ÷ 35 × 20
= 40 kg
For 10 kg
= 70 ÷ 35 × 10
= 20 kg
And, for 5 kg
= 70 ÷ 35 × 5
= 10 kg
You might be interested in
Your answer is in the picture above
Past due balance = $87.50
Late fee = 15% of $87.50 = 0.15*87.50 = $13.125
New charges = $75.00
New total = 87.50 + 13.125 + 75 = $175.625
Answer: The new total is $175.63
Here are the steps:
(3x-9)^2
(3x-9)(3x-9)
9x^2 - 27x - 27x +81
9x^2 - 54x + 81
good luck ;)
Answer:
Coordinate of Checkpoint B is (-9,5)
Step-by-step explanation:
Here is an inserted image of the graph and coordinates.
.333333.........% i cant write the little mark above it but it goes on continuosly.
