Answer:
n=53
Step-by-step explanation:
(3n-4)2
distribute the 2
you get 6n-8
plug in 53 into n 5(53)-8 and then you times 6 and 53 and get 318 subtract 8 from that and you get 310
Answer:
1. 264
2. degree: 6, term: 3xy^5
3. -60x^3-2x^2+9x
4. 6mn^3-4m
5. 8x^3-4x+2
6. -x^2-6x-13
Step-by-step explanation:
Answer:
Step-by-step explanation:
put the y intercept at 4. then go down 1 and right three, down one, then right three. go back to the y intercept and then go up one and left three, up one and left three
The probability that a student participates in both sports and music is 108/1376
<u>Explanation:</u>
Let x be the number of students participating in both sports and music
According to the question:
P(A or B) = P(A) + P(B) - P(A and B)
P(sports or music) = P(sports) + P(music) - P(sports and music)
![\frac{974}{1376} = \frac{649}{1376} + \frac{433}{1376} - \frac{x}{1376} \\\\974 = 1082 - x\\\\x = 108](https://tex.z-dn.net/?f=%5Cfrac%7B974%7D%7B1376%7D%20%3D%20%5Cfrac%7B649%7D%7B1376%7D%20%2B%20%5Cfrac%7B433%7D%7B1376%7D%20-%20%5Cfrac%7Bx%7D%7B1376%7D%20%5C%5C%5C%5C974%20%3D%201082%20-%20x%5C%5C%5C%5Cx%20%3D%20108)
P(sports and music) = ![\frac{108}{1376}](https://tex.z-dn.net/?f=%5Cfrac%7B108%7D%7B1376%7D)
Therefore, the probability that a student participates in both sports and music is 108/1376
498+345 is the answer but you divide the 3 for base of 9