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Trava [24]
4 years ago
15

If two numbers represented 2m+1 and 2m+5 have a sum of 74 find m

Mathematics
1 answer:
laila [671]4 years ago
8 0
(2m + 1) + (2m + 5) = 74

4m + 6 = 74

4m = 74 - 6

4m = 68

m = 17
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Write y=x^2-4x-1 in vertex form
Dvinal [7]

Answer:  y= (x+2)² − 5

Step-by-step explanation:

The way I got this answer is by completing the square. The first step though, when looking at this equation, is to see if we can factor it. The way to check is to look at the coefficient for x² which is 1, and the constant, in this case -1. If we multiply those together, we get  −. Now we look at the middle term, 4x. We need to find any numbers that multiply to equal  −  1x² and add to  4x. There aren't any, which means it is not factorable.

Hope I helped

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3 years ago
What is the coefficient of the xy term in the expression below? <br> 2x + 3y - 4xy - 10
alukav5142 [94]

For this case we have the following expression:

2x + 3y-4xy-10

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3x + 5

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3 0
4 years ago
Read 2 more answers
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
Please help me to evaluate 6+7=8−15
zzz [600]
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3 0
3 years ago
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VMariaS [17]

Answer:

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x is water balloons at 3 each and y is t-shirts at 7$ each.

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3 years ago
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