Find the length of the longest side of this triangle. <br><br> Please help me i’m begging you thanks

Wilmer already has 214 cards. he needs to collect 334 cards. he plans to collect 8 cards each day. find the minimum number of da

Wittaler [7]

The answer is 15 days.

The first step you need to take is to subtract the amount of cards he has from the amount of cards he needs. So 334 (needs) - 214(has) = 120 cards he still needs. So he is collecting 8 cards a day. In order to find out how many days it will take to collect the 120 cards, we need to divide 120 by 8. 120 divided by 8 is 15. So it will take 15 days collecting 8 cards a day in order to reach the 120 cards he still needs to collect.

3 0

3 years ago

A home gardener estimates that 24 apple trees will have an average yield of 104 apples per tree. But because of the size of the

d1i1m1o1n [39]

Answer:

The farmer should plant 14 additional trees, for maximum yield.

Step-by-step explanation:

Given

$Trees = 24$

$Yield = 104$

$x \to additional\ trees$

So, we have:

$Trees = 24 + x$

$Yield = 104 - 2x$

Required

The additional trees to be planted for maximum yield

The function is:

$f(x) = Trees * Yield$

$f(x) = (24 + x) * (104 - 2x)$

Open bracket

$f(x) = 24 * 104 + 104x - 24 * 2x - x * 2x$

$f(x) = 2796 + 104x - 48x - 2x^2$

$f(x) = 2796 + 56x - 2x^2$

Rewrite as:

$f(x) = - 2x^2 + 56x + 2796$

Differentiate

$f'(x) = -4x + 56$

Equate $f'(x) = -4x + 56$ to 0 and solve for x to get the maximum of x

$-4x + 56 = 0$

$-4x =- 56$

Divide by -4

$x =14$

The farmer should plant 14 additional trees, for maximum yield.

5 0

3 years ago

Brianna walks 5/12 of a mile to school everyday. So far she has walked 1/4 of a mile. How much of her walk is left?

zaharov [31]

5/12- 3/12= 2/12 so 1/6 of a mile

4 0

2 years ago

Recs

Alenkinab [10]

Answer:

hshshjsjsjejdjdjsnnsjsns

8 0

3 years ago

The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit

Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(c) The value of range is 33 and the inter-quartile range is 16.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52$

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

$Median=(\frac{n+1}{2})^{th}\ obs.$

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

$Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation$

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

$Range =Maximum-Minimum\\=69-36\\=33$

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

$IQR=Q_{3}-Q_{1}\\=60-44\\=16$

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

$s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143$

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

$s=\sqrt{s^{2}}=\sqrt{100.143}=10.01$

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

$Q_{1}-1.5QR=44-1.5\times 16=20$

Compute the value of Q₃ + 1.5 IQR as follows:

$Q_{3}+1.5QR=60-1.5\times 16=80$

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

6 0

3 years ago

Find the length of the longest side of this triangle. Please help me i’m begging you thanks