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Vaselesa [24]
3 years ago
11

If cos(x) = Negative one-fourth and tan(x) < 0, what is sin(2x) ? Negative StartFraction StartRoot 15 EndRoot Over 4 EndFract

ion Negative StartFraction StartRoot 15 EndRoot Over 8 EndFraction StartFraction StartRoot 15 EndRoot Over 8 EndFraction StartFraction StartRoot 15 EndRoot Over 4 EndFraction
Mathematics
2 answers:
WARRIOR [948]3 years ago
8 0

Answer:

-√15/8

Step-by-step explanation:

edge 2020

ivolga24 [154]3 years ago
7 0

Answer:

B. -15 square root / 8

Step-by-step explanation:

EDG2020

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Determine the sum of the parts 1 3/8 +2/3=
Mumz [18]

2 1/24

Rewriting our equation with parts separated

2/3+1+3/8

Solving the fraction parts

2/3+3/8=?

Find the LCD of 2/3 and 3/8 and rewrite to solve with the equivalent fractions.

LCD = 24

16/24+9/24=25/24

Simplifying the fraction part, 25/24,

25/24=1 1/24

Combining the whole and fraction parts

1+1+1/24=2 1/24

5 0
3 years ago
Read 2 more answers
Write square root of 64 - square root of -289 as a complex number in the form of a+bi
stellarik [79]

Answer:

\sqrt{64}-\sqrt{-289}

=8-17i

Step-by-step explanation:

\sqrt{64}=8 because 8(8)=64 and 8 is the positive square root of 64.

\sqrt{-289}=17i because 17i(17i)=289i^2=-289(-1)=-289.

\sqrt{64}-\sqrt{-289}

8-17i

8 0
3 years ago
Any math experts please factor this thank you have a blessed day
fredd [130]

Answer:

-(x-8)*(x+7)

Step-by-step explanation:

Use the commutative property

-× to the power of 2 + x+ 56

-x to the power of 2 + 8x-7x+56

-xx(x-8)-7x+56

-x*(x-8)-7(x-8)

factor out -(x-8)

-(x-8)*(x+7)

hope it helps!!

7 0
2 years ago
Read 2 more answers
The fourth grade class collected paper towel tubes for an art project. The girls brought in 31 tubes. Together the class brought
Yakvenalex [24]

Answer:

b = 46 - 31

Step-by-step explanation:

b = 46 - 31

b = 15

The boys (b) brought 15 paper towel tubes

6 0
3 years ago
Which expression is equivalent to the given expression. pls help :)
Tomtit [17]

Answer:

B

Step-by-step explanation:

\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\\(a^{m})^{n} =a^{mn}

\frac{(4m^{2}n)^{2}}{2m^{5}n}=\frac{4^{2}(m^{2})^{2}n^{2}}{2m^{5}n}\\\\\\=\frac{16m^{4}n^{2}}{2m^{5}n}\\\\\\=\frac{8m^{4}n^{2}}{2m^{5}n}\\\\\\=8m^{(4-5)}n^{(2-1)}\\\\\\=8m^{-1}n

7 0
2 years ago
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