Add them all up and divide by 6
160/6 = 26.7
Answer:
(x-7)(x-7)
Step-by-step explanation:
this is a perfect square
x^2-14x+49
take the square of the first number,
X^2 = x times x
the sign of the second number
-14x= (-)
the square of the last number
49= 7x7
to check your work you foil it out
(x-7)(x-7)
x times x = X^2
x times -7= -7x
-7 times x = -7x
-7times -7= 49
then combine like terms
x^2-7x-7x+49 = x^2-14x+49
Answer:
- 2 trees ($200 from either service)
- c=100+50t
- c=80+60t
Step-by-step explanation:
It can work well to solve problems like this by considering how many times the difference in per-tree costs it takes to make up the difference in one-time costs.
Here the difference of one-time costs is $20, and the difference in per-tree costs is $10, so it takes the pruning of 2 trees for the per-tree cost difference to equal the one-time cost difference (2×10 = 20).
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The cost equations are ...
cost = (one-time cost) + (per tree cost) × (number of trees)
c = 100 + 50t . . . . . company A
c = 80 + 60t . . . . . . company B
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If you use these equations to solve the problem, you want to find t such that the two costs are equal:
100 +50t = 80 +60t
(100 -80) = t(60 -50) . . . . . . . subtract 80+50t, factor out t
(100 -80)/(60 -50) = t . . . . . . . looks a lot like the verbal description above
The difference in fixed price divided by the difference in per-tree cost) is the number of trees required to make costs equal.
Answer:
Pauli had 320 chips at the beginning of the game
Step-by-step explanation:
denoting x as the number of initial chips then
1°) lost half her total = x/2 , remaining after that = x-x/2= x/2
2°) won 54 chips, now Pauli has 54+x/2
3°) lost half her total again , now Pauli has 1/2( 54+x/2)
4°) won 50 chips , finally Pauli has 1/2( 54+x/2) + 50
therefore
1/2( 54+x/2) + 50 = 157
54+x/2 = (157-50)*2 = 214
x/2 = 214-54 = 160
x= 160*2 = 320 chips
x= 320 chips
then Pauli had 320 chips at the beginning of the game
