The original quantity is 10 and the new quantity is 13% what is the percent change is it increase or decrease
2 answers:
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To prove that the given triangle is an isosceles, two of its sides must have equal lengths.
Between D(2,-5) and E(6,-1):
d = √(6 - 2)² + (-1 - ⁻5)² = 4√2
Between E(6,-1) and F(5,6):
d = √(5 - 6)² + (6 - ⁻1)² = 5√2
Between D(2,-5) and F(5,6)
d = √(5 - 2)² + (6 - ⁻5)² = √130
<em>Since there are no equal lengths, the triangle is NOT an isosceles triangle.</em>
The bisector of angle F is a line segment from vertex F to the midpoint of line DE.
Midpoint: x = (2+6)/2 = 4; y = (-5+-1)/2 = -3
The midpoint is at (4,-3).
The equation of the line follows the point-slope formula:
y - y₁ = [(y₂ - y₁)/(x₂ - x₁)](x - x₁)
Substituting using points (5,6) and (4,-3)
y - 6 = [(⁻3 - 6)/(4 - 6)](x - 5)
y - 6 = (9/2)(x - 5)
2(y - 6) = 9(x - 5)
2y - 12 = 9x - 45
<em>2y - 9x = -33 </em>
Between D(2,-5) and E(6,-1):
d = √(6 - 2)² + (-1 - ⁻5)² = 4√2
Between E(6,-1) and F(5,6):
d = √(5 - 6)² + (6 - ⁻1)² = 5√2
Between D(2,-5) and F(5,6)
d = √(5 - 2)² + (6 - ⁻5)² = √130
<em>Since there are no equal lengths, the triangle is NOT an isosceles triangle.</em>
The bisector of angle F is a line segment from vertex F to the midpoint of line DE.
Midpoint: x = (2+6)/2 = 4; y = (-5+-1)/2 = -3
The midpoint is at (4,-3).
The equation of the line follows the point-slope formula:
y - y₁ = [(y₂ - y₁)/(x₂ - x₁)](x - x₁)
Substituting using points (5,6) and (4,-3)
y - 6 = [(⁻3 - 6)/(4 - 6)](x - 5)
y - 6 = (9/2)(x - 5)
2(y - 6) = 9(x - 5)
2y - 12 = 9x - 45
<em>2y - 9x = -33 </em>
Answer:
Part 1) ----->
Part 2) ------>
Part 3) ----->
Part 4) ----->
Part 5) ------>
Step-by-step explanation:
Part 1) we have
To calculate the subtraction convert the mixed numbers to an improper fractions
substitute
Convert to mixed number
Part 2) we have
To calculate the subtraction eliminate the parenthesis first
Part 3) we have
To calculate the subtraction convert the mixed numbers to an improper fractions
substitute
Eliminate the parenthesis
Convert to mixed number
Part 4) we have
To calculate the subtraction eliminate the parenthesis first
Part 5) we have
To calculate the subtraction convert the mixed numbers to an improper fractions
substitute
Eliminate the parenthesis
