Answer:
Part 19) x=5
Part 20) x=-3
Step-by-step explanation:
Problem 19) Find the value of x so that f(x)=7
step 1
Find the intersection point of the given line in the graph with the line y=7
The intersection point is (5,7)
see the attached figure
therefore
The x-coordinate of the intersection point is the value of x when f(x)=7
x=5
f(5)=7
Problem 20) Find the value of x so that f(x)=7
step 1
Find the intersection point of the given line in the graph with the line y=7
The intersection point is (-3,7)
see the attached figure
therefore
The x-coordinate of the intersection point is the value of x when f(x)=7
x=-3
f(-3)=7
Answer:
C. 
Step-by-step explanation:
Given:
Add the two equations, we get
Therefore, the correct option is option C.
In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer:
(x +1) (x + 5)
Step-by-step explanation:
Factorization of x²+6x+5
To factorise this quadratic expression we'll find 2 factors of 5 that when added gives the coefficient of x which is
Factors = +1 and +5
Sum = +6, product = +5
Rewriting equation
x² + x + 5x + 5
Factorising
x ( x +1) +5 ( x + 1)
(x +1) (x + 5)
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