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3 years ago

1.14 what is the answer to this one

Mathematics

1 answer:

UNO [17]3 years ago

5 0

Answer:

0.001

Step-by-step explanation:

So... errr... brainly doesn't allow cheating but i want to help so... here:

10^(-n)= 1/(10^n) following this, 10^-3=1/10^3 = 1/1000 = the second option (0.001)

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HELP PLS!!!!!!!!!! you get 5 pointsssssss PLS I BEG QUICK!!!!!

STALIN [3.7K]

Answer:

6.5 mph

Step-by-step explanation:

Pace per mile

09 : 13.85

min : sec

Speed

0.1083 miles per minute

6.5 miles per hour

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3 years ago

Read 2 more answers

Assume {v1, . . . , vn} is a basis of a vector space V , and T : V ------> W is an isomorphism where W is another vector spac

Degger [83]

Answer:

Step-by-step explanation:

To prove that $w_1,\dots w_n$ form a basis for W, we must check that this set is a set of linearly independent vector and it generates the whole space W. We are given that T is an isomorphism. That is, T is injective and surjective. A linear transformation is injective if and only if it maps the zero of the domain vector space to the codomain's zero and that is the only vector that is mapped to 0. Also, a linear transformation is surjective if for every vector w in W there exists v in V such that T(v) =w

Recall that the set $w_1,\dots w_n$ is linearly independent if and only if the equation

$\lambda_1w_1+\dots \lambda_n w_n=0$ implies that

$\lambda_1 = \cdots = \lambda_n$ .

Recall that $w_i = T(v_i)$ for i=1,...,n. Consider $T^{-1}$ to be the inverse transformation of T. Consider the equation

$\lambda_1w_1+\dots \lambda_n w_n=0$

If we apply $T^{-1}$ to this equation, then, we get

$T^{-1}(\lambda_1w_1+\dots \lambda_n w_n) =T^{-1}(0) = 0$

Since T is linear, its inverse is also linear, hence

$T^{-1}(\lambda_1w_1+\dots \lambda_n w_n) = \lambda_1T^{-1}(w_1)+\dots + \lambda_nT^{-1}(w_n)=0$

which is equivalent to the equation

$\lambda_1v_1+\dots + \lambda_nv_n =0$

Since $v_1,\dots,v_n$ are linearly independt, this implies that $\lambda_1=\dots \lambda_n =0$ , so the set $\{w_1, \dots, w_n\}$ is linearly independent.

Now, we will prove that this set generates W. To do so, let w be a vector in W. We must prove that there exist $a_1, \dots a_n$ such that

$w = a_1w_1+\dots+a_nw_n$

Since T is surjective, there exists a vector v in V such that T(v) = w. Since $v_1,\dots, v_n$ is a basis of v, there exist $a_1,\dots a_n$ , such that

$a_1v_1+\dots a_nv_n=v$

Then, applying T on both sides, we have that

$T(a_1v_1+\dots a_nv_n)=a_1T(v_1)+\dots a_n T(v_n) = a_1w_1+\dots a_n w_n= T(v) =w$

which proves that $w_1,\dots w_n$ generate the whole space W. Hence, the set $\{w_1, \dots, w_n\}$ is a basis of W.

Consider the linear transformation $T:\mathbb{R}^2\to \mathbb{R}^2$ , given by T(x,y) = T(x,0). This transformations fails to be injective, since T(1,2) = T(1,3) = (1,0). Consider the base of $\mathbb{R}^2$ given by (1,0), (0,1). We have that T(1,0) = (1,0), T(0,1) = (0,0). This set is not linearly independent, and hence cannot be a base of $\mathbb{R}^2$

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3 years ago

Find an equation of the line through (3,7) and parallel to y=3x-1

iren2701 [21]

Answer:

y = 3x -2

Step-by-step explanation:

If the line is parallel, that means it has the same slope. The given equation had a slope of 3, so the new line must also have a slope of 3.

You can plug the given coordinates into the slope-intercept form with a slope of 3 to find your answer.

y = m*x + b

7 = 3*3 + b

7 = 9 + b

-2 = b

y = 3x -2

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4 years ago

Hong's gas tank is 1/2 full. After he buys 5 gallons of gas, it is 5/6 full. How many gallons can Hong's tank hold?

quester [9]

Answer:

I'm pretty sure your answer would be B.

Step-by-step explanation:

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3 years ago

natalie guessed on the last four true or false questions on her math quiz. what is the probability that she got all four quiz qu

Verizon [17]

Each question is either true or false, so the sample space is 2, true and false, two states only.

what's the probability she got one correct, well, the favorable outcomes is 1, possible outcomes is 2, so 1/2.

what's the probability that she got all four correct, we simply multiply the probability of each,

$\bf \cfrac{1}{2}\cdot \cfrac{1}{2}\cdot \cfrac{1}{2}\cdot \cfrac{1}{2}\implies \cfrac{1}{16}\implies 0.0625\qquad or\qquad 6.25\%$

7 0

3 years ago