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Bezzdna [24]
2 years ago
7

What is fixed income

Mathematics
1 answer:
SOVA2 [1]2 years ago
4 0

Answer:

Fixed Income Mathematics features material and analysis on yield measures for fixed rate bonds and floating rate bonds, key rate duration and yield curve curvature, cash flow characteristics of collateralized debt obligations, and much more.

Fixed income broadly refers to those types of investment security that pay investors fixed interest or dividend payments until its maturity date. At maturity, investors are repaid the principal amount they had invested. Government and corporate bonds are the most common types of fixed-income products.

Step-by-step explanation:

Some examples are:

Bonds. ...

Savings bonds. ...

Guaranteed Investment Certificates (GICs) ...

Treasury bills. ...

Banker's Acceptances. ...

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Fantom [35]
B) is correct
a=-4
b=9t
(a+b)(a-b)=a^2-b^2=16-81t^2


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2 years ago
Find BC<br>AC = 7<br>BD = 7.5<br>DE = 1.5<br>AE = 11​
tatuchka [14]

5

CE=AE-AC=4

CD=CE-DE=4-1.5=2.5

BC=BD-CD=7.5-2.5=5

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3 years ago
What is the nearest whole percent of 45
kvv77 [185]

Answer:

Step-by-step explanation: 45% based on the way you state the question. 45% is a whole percent.

6 0
2 years ago
Read 2 more answers
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
A cone has a volume of 942 in.³ and a height of 9 inches what is the radius of the cone use 3.14 for pie
bija089 [108]

Answer:

r = 51.96 inches

Step-by-step explanation:

V_{cone} = \pi {r}^{2} h  \\  \\  \implies \: r^{2}  =  \frac{V_{cone}}{\pi h } \\  \\  \implies \:  r^{2} =  \frac{942}{3.14 {(9) } }\\  \\  \implies \:  r^{2} =  \frac{942}{3.14 {(9) } } \\  \\  \implies \:  r^{2} =2700 \\  \\  \implies \:  r= \sqrt{2700}  \\  \\  \implies \:  r=51.96 \: inches

8 0
2 years ago
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