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3 years ago

Can someone please help me. I’ll mark u brainiest.

Mathematics

1 answer:

snow_lady [41]3 years ago

6 0

Answer:

y = 240,000(1.048)^t

Step-by-step explanation:

Initial population: p = 240,000

Annual growth rate: 4.8% = 0.048

Number of years: t

Population in year t: y

y = p(1 + r)^t

y = 240,000(1 + 0.048)^t

y = 240,000(1.048)^t

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I really need help with this

aniked [119]

Answer:

5√202

Step-by-step explanation:

By Pythagoras theorem,

x^2 = 45^2 + 55^2

= 2025 + 3025

x^2 = 5050

x = 5√202

5 0

3 years ago

Rewrite 5 ⋅ x + 5 ⋅ 8 using parentheses.

Lera25 [3.4K]

Answer:

(5 ⋅ X) + (5 ⋅ 8) =

Step-by-step explanation:

7 0

2 years ago

What is the slope of the line given by the equation y=-1/3x? Entee your answer as an integer or fraction in lowest terms.

Serhud [2]

-1/3

really? it's that easy dude.

whatever number is next to x, like say, 3x, that number would be the slope, so it would be 3.

hope it helped.

6 0

3 years ago

Find the area of a circle with a diameter of 14 meters. Round your answer to the nearest hundredth of a square meter.

Jlenok [28]

To find the area of the circle:

⇒ need to know the formula: $\pi r^{2}$

r: radius or half of diameter's length ⇒ 7 meters

Let's calculate:

$Area = \pi (7)^2=49\pi =153.9380m^3$

The problem asks us to round to the nearest hundreth:

$Area = 153.94m^3$

Answer: $153.94m^3$

Hope that helps!

4 0

1 year ago

△klm, lm=20 sqrt 3 m∠k=105°, m∠m=30° find: kl and km

Anarel [89]

Answer:

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

MK = $\frac{40\sqrt{3}}{1+\sqrt{3}}$ = 25.36

Explanation:

According to the Law of Sines:

$\frac{a}{sinA}=\frac{b}{sinB}= \frac{c}{sinC}$

where:

A, B, and C are angles

a, b, and c are the sides opposite to the angles

First of all, let's find m∠L: the sum of the angles of a triangle is 180°, therefore

m∠K + m∠L + m∠M = 180°

m∠L = 180° - m∠K - m∠M

m∠L = 180° - 105° - 30°

m∠L = 45°

Now, we can apply the Law of Sines to our case (see picture attached):

$\frac{LM}{sinK}=\frac{MK}{sinL}=\frac{KL}{sinM}$

Let's solve one side at the time:

$\frac{LM}{sinK}=\frac{MK}{sinL}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{MK}{sin(45)}$

$MK = \frac{20\sqrt{3} }{sin(105)} \cdot sin(45)$

MK = $\frac{40\sqrt{3} }{1+\sqrt{3} }$ = 25.36

Similarily:

$\frac{LM}{sinK}=\frac{KL}{sinM}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{KL}{sin(30)}$

$KL = \frac{20\sqrt{3} }{sin(105)} \cdot sin(30)$

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

8 0

3 years ago