<h3>hello!</h3>
We're given a point that the line intersects and its slope.
Let's use Point-slope:-

y1 = -5
m=-5
x1=-1


Convert to slope-intercept:-


Finally,

<h3>note:-</h3>
Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)
Answer:
The half life of the car is 3.98 years.
Step-by-step explanation:
The value of the car after t years is given by the following equation:

In which V(0) is the initial value and r is the constant decay rate, as a decimal.
The value of a certain car decreases by 16% each year.
This means that 
So



What is the 1⁄2-life of the car?
This is t for which V(t) = 0.5V(0). So







The half life of the car is 3.98 years.
Answer:
1E-6 m^3 or 0.000001 m^3
Step-by-step explanation:
1cm^3 = 1cm*1cm*1cm
1m^3 = 100cm*100cm*100cm = 1000000 cm^3
1/1000000 = 1E-6 m^3
Leave a like and mark brainliest if this helped
Leave a like and mark brainliest if this helped
Answer:
X= 9/2
Alternative form
x=4 1/2, x=4.5
Step-by-step explanation:
*= Multiply
1. log (little 10 under) (2)*(3x-1)= log (little 10 under) (2)*(x+8)
2. then divide both side by log (little 10 under (2))
3. 3x-1=x+8
4. move variable to the left side and change its sign
5. 3x-x-1=8
6. then move constant to the right side and change its sign
7. 3x-x=8+1
8. collect like terms
9. 2x=8+1
10. add 8+1
11. 2x=9
12. then divide both sides by 2
13. 2/2 9/2
14. 2/2 cancels out so x=9/2 is the answer