Please helpabd=58 and bdc=32 what is the measure of adb
1 answer:
Answer:
<ADB = 61degrees
Step-by-step explanation:
From the diagram shown, triangle ADB is isosceles since they projected out from the chord AD. Hence;
<ABD + <ADB + <BAD = 180
Since <ADB = <BAD, then;
<ABD + <ADB + <ADB = 180
Given that:
<ABD = 58degrees
58 + 2<ADB = 180
2<ADB = 180 - 58
2<ADB = 122
<ADB = 122/2
<ADB = 61degrees
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