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vfiekz [6]
3 years ago
9

Suppose M is the midpoint of FG. Find the missing measure.

Mathematics
1 answer:
Arlecino [84]3 years ago
7 0

A midpoint divides a line segment into equal halves.

The value of x is 3.4

Given that:

FG = 11x - 15.6

MG = 10.9

Since M is the midpoint, then:

FG = 2 \times MG

So, we have:

11x - 15.6 =2 \times 10.9

11x - 15.6 =21.8

Collect like terms

11x =15.6 +21.8

11x =37.4

Solve for x

x =3.4

<em>Hence, the value of x is 3.4</em>

Read more about midpoints at:

brainly.com/question/2441957

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\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

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Write the divide fraction horizontally:
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= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

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Factorise the numerators and denominators when possible:
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= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

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Convert the divide fraction to multiplication fraction
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= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

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Cancel the factors
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= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

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