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rodikova [14]
3 years ago
10

Please help me thank ​

Mathematics
1 answer:
irina1246 [14]3 years ago
4 0

Answer:

a) equilateral

b) Isosceles

c) scalene

d) right angle

e) acute angle

f) obtuse angle

It is correct answer

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Integers<br>53 + (-26 )​
-BARSIC- [3]
<h2>✨ Question ✨</h2>

53 + (-26 )

<h2>✨ Answer ✨</h2>

\:  \:  \:  \:  \: \:  \:  \:  \:   \purple{ \boxed{ \boxed{ \huge{ \tt{ \: 37 \: }}}}}

6 0
2 years ago
What are the zeros of the function below?
Ivan
When you want to find zeros of rational expression you need to find at which points numerator is equal to zero. In this case, we have the product of three expressions.
x(x-1)(x+11)=0
A product is equal to zero whenever one of the factors is equal to zero. 
That means that zeros of our functions are:
1)x=0
2)x-1=0
x=1
3)x+11=0
x=-11
The final answer is a. Function has zeros at (0, 1, -11).

3 0
3 years ago
how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^
PIT_PIT [208]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$150\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &13&#10;\end{cases}&#10;\\\\\\&#10;A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589
3 0
3 years ago
A line includes the points (10,-5) and (-10,-1). What is the equation in slope intercept form?
Elodia [21]

\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-10}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{-10-10}\implies \cfrac{-1+5}{-20}\implies \cfrac{4}{-20}\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=-\cfrac{1}{5}(x-10) \\\\\\ y+5=-\cfrac{1}{5}x+2\implies y=-\cfrac{1}{5}x-3

8 0
3 years ago
Please help!!!!!!!​
Serhud [2]

Answer:

152

Step-by-step explanation:

12+16=28 so 180 is the total and 180-28=<u>152</u>

<u />

3 0
3 years ago
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