All categories

3 years ago

PLEASE HELP. i’ll give brainliest if you want!

Mathematics

2 answers:

vaieri [72.5K]3 years ago

4 0

Answer:

Dharma

Step-by-step explanation:

id love a brainliest also.. what subject is this and in which country??

hammer [34]3 years ago

3 0

Answer:

Dharma

Step-by-step explanation:

looked it up

You might be interested in

There are 3 3/4 pounds of bricks in a bag. Each brick weighs 5/8 of a pound. How many bricks are in the bag.

Bess [88]

Answer: There are 6 bricks in the bag.

Step-by-step explanation:

Convert from mixed number to decimal number. To do it, divide the numerator of the fraction by the denominator and add the result to the whole number part. Then:

$3\frac{3}{4}\ lb=(3+0.75)\ lb=3.75\ lb$

Convert from fraction to decimal number. To do it you need to divide the numerator by the denominator. Then, you get:

$\frac{5}{8}lb=0.625\ lb$

Let be "x" the number of bricks in the bag<em>.</em>

<em> </em>Based on the information given in the exercise, you can set up the following proportion:

$\frac{1}{0.625}=\frac{x}{3.75}$

Finally, you must solve for "x" in order to find its value. This is:

$(3.75)(\frac{1}{0.625})=x\\\\x=6$

8 0

3 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0

2 years ago

Find all the zeros of <br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7B6x%7D%5E%7B4%7D%20%20%20-%20%20%7B7x%7D%5E%7B

Svetradugi [14.3K]

Answer:

{-1, 1/2, 2/3, 1}

Step-by-step explanation:

I find a graphing calculator to be a most useful tool for problems like this. (See attached.)

_____

First of all, observe that the constant is -2, so 0 is not a zero.

It is often useful to look at the sum of coefficients. Here, that is 0, indicating 1 is a zero.

You can divide that out, or simply continue by looking at the sum of coefficients with odd-degree terms negated. Then you have 6 +7 -4 -7 -2 = 0, indicating -1 is also a zero.

At this point, it can be useful to divide out the factors you know. The synthetic division tableaus attached show that work. First is division by (x+1), then by (x -1).

The result of doing that is the quadratic ...

6x^2 -7x +2 = 0

This can be factored ...

(6x^2 -3x) -(4x -2) = 0 . . . . . . rewrite -7x and group term pairs

3x(2x -1) -2(2x -1) = 0 . . . . . . . factor each pair

(3x -2)(2x -1) = 0 . . . . . . the factorization of the remaining quadratic

The zeros of this are the values of x that make the factors zero: 2/3 and 1/2.

The zeros of the given function f(x) are x ∈ {-1, 1/2, 2/3, 1}.

5 0

3 years ago

What is the common ratio for the geometric sequence?

Helen [10]

Note this pattern: Mult. 24 by (-1/4) produces -6.
Mult -6 by (-1/4) produces 6/4 = 3/2
Mult. 3/2 by (-1/4) produces 3/8

Looks as though you copied the problem down incorrectly. You wrote 32 for 3/2 and -38 for -3/8.

The common ratio is -1/4.

5 0

4 years ago

Read 2 more answers

Can you help me please.

laila [671]

Answer:

Step-by-step explanation:

I just kept going up by 3 until the 20th term

5 0

3 years ago

Read 2 more answers