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Anarel [89]
3 years ago
11

(GEOMETRY) What is the length of the radius of the circle?

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

r=\frac{5}{2}\sqrt{2}

Step-by-step explanation:

<u>Triangles And Circles</u>

If a right triangle is inscribed in a circle (or the circle is circumscribed around the right triangle), then the hypotenuse of the triangle is the diameter of the circle.

The right triangle has both legs of known lengths, thus the hypotenuse (the diameter of the circle is):

d^2=5^2+5^2

d^2=25+25=50

d=\sqrt{50}

Since 50=2*25:

d=5\sqrt{2}

Thus the radius of the circle is:

r=\frac{d}{2}

r=\frac{5\sqrt{2}}{2}

\boxed{r=\frac{5}{2}\sqrt{2}}

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Rewrite it in the form a^2 - b^2, where a = 5x and b = 8

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Easy, showing work,

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