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Yuri [45]
3 years ago
9

The ratio of roses to tulips is in an arrangment is 2/3. The total number of flowers is 25. How many tulips are there?

Mathematics
1 answer:
blagie [28]3 years ago
7 0

Answer: there are 15 tulips

Step-by-step explanation:

roses : tulips

2 : 3

2x + 3x = 25

5x = 25

x = 25/5

x= 5

roses:

2x

2(5)

10

tulips:

3x

3(5)

15

check:

10+15 =25

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A line is perpendicular to y = {2/3x + 2/3}
Anna35 [415]

Answer: y = (-3x/2) + 1

Step-by-step explanation:

From the standard equation y = mx + c, the slope of the equation is 2/3. Therefor slope of a line perpendicular to it will be -3/2.

Hence the equation will be

y = (-3x/2) + c

As this line passes through (-2,4), putting these values in this equation gives  c = 1.

Hence the answer is y = (-3x/2) + 1

3 0
3 years ago
A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in
777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

<em><u>Verify each statement</u></em>

<em>A) Each pack of folders has a volume of 60 cubic inches.</em>

The statement is True

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

<em>B) The box has a volume of about 720 cubic inches</em>

The statement is True

Because

The volume of the box is equal to the volume  of one pack of folders multiplied by 12

so

V=(12)60=720\ in^{3}

<em>C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches</em>

The statement is False

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}

900\ in^{3}\neq 1,200\ in^{3}

<em>D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.</em>

The statement is True

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}

1,200\ in^{3}= 1,200\ in^{3}

<em>E) Each pack of folders has a volume of 24 cubic inches.</em>

The statement is False

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

7 0
3 years ago
Please help me with this question!
MakcuM [25]
<span><span>x=<span><span>​<span>20</span></span>​<span>​<span><span>(y−3)</span><span><span>​2</span><span>​​</span></span></span></span><span>​​</span></span>−1</span><span>
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5 0
3 years ago
A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c
Alenkinab [10]

Answer:

C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

l\times b\times h

where l is the length, b is the base and h is the height.

Volume of box =

s^2h = 150\\\\h = \dfrac{150}{s^2}

Area of base =

\text{side}\times \text{side} = s^2

Cost of concrete for the base = $4

Cost of base($) = 4s^2

Area of roof =

\text{side}\times \text{side} = s^2

Cost of material for the roof = $2

Cost of roof ($) = 2s^2

Area of 4 walls =

4\times (sh)\\=4sh

Cost of material for the side = $2.50

Cost of material of side($) =

2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}

is the required cost function.

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