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Leto [7]
3 years ago
11

Help plssssss this is due today! This composite figure is made up of three simpler shapes. What is the area of the figure?

Mathematics
2 answers:
Alexxandr [17]3 years ago
3 0
The correct answer is D- 55 square cm

SashulF [63]3 years ago
3 0

Answer:

D 55 sqaure cm

Step-by-step explanation:

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Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
Solve for h: V=1/3b^2h
yanalaym [24]

Answer:

Step-by-step explanation:

8 0
3 years ago
Simplify the polynomial expressions by combining like terms, and then multiply the resulting binomial expressions to find their
Lesechka [4]
For this case we have the following expression:
 (8x - 9 - 2x) (15 + 5x - 5)

 The first thing we must do is to rewrite the expression as the product of two binomials.
 To do this, we add similar terms.
 We have then:
 (6x - 9) (5x + 10)

 Then, doing distributive property we have:
 30x ^ 2 + 60x - 45x - 90

 Adding similar terms:
 30x ^ 2 + 15x - 90
 Answer:
 
The simplified expression is:
 
30x ^ 2 + 15x - 90
7 0
4 years ago
Please help, I'll mark brainlist
My name is Ann [436]
7=x this is for the first one but you have to 1
3
=

2
1
1
3
=
x
21
31​=21x​
2
1
⋅
1
3
=
2
1
⋅

2
1
21
⋅
1
3
=
21
⋅
x
21
21⋅31​=21⋅21x​
Multiply the numbers
Cancel multiplied terms that are in the denominator
7
=
2
1
⋅

2
1
7
=
21
⋅
x
21
7=21⋅21x​
7
=

7
=
x
7=x
7
=

7
=
x
7=x

5 0
3 years ago
The Black line is the graph of y=c. Which of these equations could represent the blue line?
galben [10]
C. y = 0.5x.

The coefficient of x is the slope of the line. From the picture, you can see that the slope of the blue line is half the slope of the black line.
3 0
3 years ago
Read 2 more answers
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