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Juliette [100K]
3 years ago
10

Find the principal of interest!! random answers will be reported

Mathematics
2 answers:
Yanka [14]3 years ago
7 0

Answer:

eeee 4c4 202

Step-by-step explanation: 1990

Reptile [31]3 years ago
6 0

Answer:

I have it in above pic hope it

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4 3/2 solve in indices​
mylen [45]

Answer:

(2^2)^3/2 = (2)^3 = 8

Step-by-step explanation:

So to solve (4)^3/2 ,you have to realise that you need to remove the denominator in the exponent value which in this case is 2

In order to remove the 2,you would need a 2 in the numerator of the exponent .While understanding all this the value 4 can be equated as 2^2.

Thus your means of getting a 2 in the numerator is solved by simply replacing the 4 with 2^2

Thus what you will get is (2^2)^3/2

Now we have a property in exponent where

(x^m)^n = (x)^mn

Thus (2^2)^3/2 = (2)^3 =8

3 0
3 years ago
I continue to be bad at math please help me with it
Aleksandr-060686 [28]

Answer:

24

Step-by-step explanation:

There are 4 cups in one US quart, 4*6 is 24.

7 0
3 years ago
A glass dome for a lighting fixture is in the shape of a hemisphere. The circumference of the great circle of the hemisphere is
Alona [7]

Answer:

A and B

Step-by-step explanation:

4 0
4 years ago
You are constructing a metal border of uniform width for a rectangular wall mirror that measures 20 inches by 24 inches. You hav
kirill115 [55]

Answer:

The frame will be 4 inches in width

Step-by-step explanation:

The length of the outside is 24+2x

The width of the outside is 20+2x

(24+2x)(20+2x) - 20(24) = 416

480 + 40x + 48x + 4x2 - 480 = 416

4x2 + 88x - 416 = 0

x2 + 22x - 104 = 0

(x+26)(x-4) = 0

x = -26 or x=4

The frame will be 4 inches in width

6 0
2 years ago
In a parallel circuit, ET = 240 V, R = 27 kΩ, and XL = 47 kΩ. What is IT?
TEA [102]

Answer:


Step-by-step explanation:

To find

total current= IT =?

in parallel resistor inductor circuit =ET =EL= ER = 240V

IT =  Square root [ (IR)² + (IL)²]

IR = ER/R

 = 240V / 27kΩ

 = 240V / 27000Ω                  ( IKΩ = 1000Ω)

  = 0.008 ampere.

IL = EL / XL

  = 240V / 47 KΩ

  =240 V / 47000Ω          ( IKΩ = 1000Ω)

  = 0.005 amperes

IT = Square root [ (0.008)² +( 0.005) ²]

 = Square root [ 8.9 ×10^-5]

 = 9.4×10^-3 ampere



7 0
3 years ago
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