Answer:
7.75
Step-by-step explanation:
Given:
The given system of equations is:
To find:
The solution to this system of equations by graphing.
Solution:
We have,
The table of values for first equation is:
x y
0 1
1 -1
Plot the points (0,1) and (1,-1) on a coordinate plane and connect them a straight line.
The table of values for second equation is:
x y
0 -4
2 -3
Plot the points (0,-4) and (2,-3) on a coordinate plane and connect them a straight line.
The graphs of given equations are shown in the below figure.
From the below figure, it is clear that the lines intersect each other at point (2,-3). So, the solution of the given system of equations is (2,-3).
Therefore, the solution to this system of equations is:
x-coordinate: 2
y-coordinate: -3
Answer:
<u>There</u><u> </u><u>is</u><u> </u><u>no</u><u> </u><u>solution</u>
Answer:
The question isn't complete, so I will assume that we want to find the probability of moving out of the start position.
First, we know that there is a total of 50 cards.
of these 50 cards, we have:
10 with the number 1
10 with the number 2
10 with the number 3
10 with the number 4
10 with the number 5
To move out of the starting position, we need to draw a 2 or a 3.
And we have 10 of each, then there are 20 cards that allow us to move out of the start position.
The probability of moving out of the starting position in the first draw, is equal to the quotient between the number of cards that allow us to move out of the starting position (20) and the total number of cards (50), this is:
P = 20/50 = 2/5 = 0.4
Answer:
8x
Step-by-step explanation:
2+x=2x
2x times 4=8x