Answer:
A function with out parameters cannot take any arguments or perform operations on variables passed in. A function with parameters can.
Answer:
1. This is because non-essential parts of the analog data is cut of so as to represent the analog data digitally.
2. This is because it mirrors closely to the original analog material.
3. i. Temperature ii. Speed ii. Distance iv. Electric current
Explanation:
1. How is a digital representation of analog data a form of abstraction?
Digital representation of analog data is a form of abstraction because, since abstraction, which is the removal of non-essential parts of a material so as to reduce complexity, also non-essential parts of the analog data is cut of so as to represent the analog data digitally.
2.Why is the quality of the photo, music, etc better when more samples are taken?
The quality of these items is better because, as more samples are taken, it reduces the error in the sampling and the item(photo, music etc) mirrors closely to the original analog material.
3. What other examples of analog data can you think of?
i. Temperature ii. Speed ii. Distance iv. Electric current
Answer:
Bookmarking
Explanation:
Bookmarking site are social sites that allow it members or users to organize tag and share links to media and other online content on the internet using their own web service instead of using the regular browser's bookmarking feature. some examples include Pinterest, Reddit, Dribble, Pocket, Digg, Slashdot, StumbleUpon.
I haven't seen your lesson, but I would:
- Not use PPTP, but rather OpenVPN or equivalent
- Consider using client certificates
- Consider using a token generator (a piece of hardware that generates access codes).
Answer:
void swapAll(int *a1, int *a2, int n){
int i;
int tmp[n];
for(i = 0; i < n; i++){
tmp[i] = a1[i];
a1[i] = a2[i];
a2[i] = tmp[i];
}
}
Explanation:
You just need a temporary structure.
I am going to write a c script, in which a1 and a2 are the arrays and n is the length of the arrays.
void swapAll(int *a1, int *a2, int n){
int i;
int tmp[n];
for(i = 0; i < n; i++){
tmp[i] = a1[i];
a1[i] = a2[i];
a2[i] = tmp[i];
}
}