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viktelen [127]
3 years ago
11

How is a digital representation of analog data a form of abstraction? Why is the quality of the photo, music, etc better when mo

re samples are taken? Music is an example of analog data. What other examples of analog data can you think of?
Computers and Technology
1 answer:
Alex3 years ago
7 0

Answer:

1. This is because non-essential parts of the analog data is cut of so as to represent the analog data digitally.

2. This is because it mirrors closely to the original analog material.

3. i. Temperature ii. Speed ii. Distance iv. Electric current

Explanation:

1. How is a digital representation of analog data a form of abstraction?

Digital representation of analog data is a form of abstraction because, since abstraction, which is the removal of non-essential parts of a material so as to reduce complexity, also non-essential parts of the analog data is cut of so as to represent the analog data digitally.

2.Why is the quality of the photo, music, etc better when more samples are taken?

The quality of these items is better because, as more samples are taken, it reduces the error in the sampling and the item(photo, music etc) mirrors closely to the original analog material.

3. What other examples of analog data can you think of?

i. Temperature ii. Speed ii. Distance iv. Electric current

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Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
4 years ago
A program is considered portable if it . . . can be rewritten in a different programming language without losing its meaning. ca
Semenov [28]

Answer:

Can be executed on multiple platforms.

Explanation:

A program is portable if it is not platform dependent. In other words, if the program is not tightly coupled to a particular platform, then it is said to be portable. Portable programs can run on multiple platforms without having to do much work. By platform, we essentially mean the operating system and hardware configuration of the machine's CPU.

Examples of portable programs are those written in;

i. Java

ii. C++

iii. C

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3 years ago
When I use
slega [8]

Answer:

If it works then no, if it doesn't then yes

Explanation:

Code Academy probably runs either way because it is not taking this as a intense class.

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Central processing Unit
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Which of the following is an example of an inline element? A. B. C. D.
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