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maks197457 [2]
3 years ago
10

Which software documentation guideline did the IEEE establish?

Computers and Technology
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

B

Explanation:

I am big brain

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1. It defines the amount of white space that appears at the top, bottom, left, and right edge of
LekaFEV [45]

Answer:

Margin is the correct answer to the given question .

Explanation:

The main objective of the margin is to setting the white space that are showing up at the top , bottom, left and the right corners of the file or the document .

Following are steps to setting the white space that are showing up at the top , bottom, left and the right corners of the file or the document

  • Firstly click on the page layout  options  .
  • After that click on the margin tab .In this tab you will given the the top, bottom, left, and right margin according to your need
  • Finally click on ok to finish them .
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True or false Rough estimates indicate that point suspension of your driver's license can average anywhere between $3,000+ and $
leva [86]
True however it’s also depends on where you live but for this purpose it’s true
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What information is displayed in the message header of a received message? Check all that apply.
Aleks04 [339]

Answer:

the subject of the message

the sender's name

the recipient's name

the date and time when the message was received

Explanation:

Various information is displayed in the header of the message of a received message. And they are the subject of the message, which briefs what is there inside the message. And it mentions the sender's name as well as the recipient's name, and finally, the date and the time as well are stated that explains exactly when the message was being received. And all this information is shown in the header of the message.

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3 years ago
15)Which of the following statements is generally true about a V8 engine...
Vladimir79 [104]

Answer: Generally, there is an increase in power with a V8 engine.

Explanation:

A V8 engine has a bigger engine that cars with a V4 or V6 engines. They can go faster and gain speed at a faster rate than the other cars. They are not good on gas and use more gas than other cars with smaller engines.

Two things that are great about having a V8 engine is the torque and the power output. One of the most powerful engines with a V8 is a Dodge Challenger SRT. These engines are usually in bigger trucks and sports cars.

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3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
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