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3 years ago

27q = –513 Solve. Please

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

Answer:

-19

Step-by-step explanation:

To solve for q, you need to isolate q. To do, this you would divide both sides by 27.

27q = –513

27q/27 = –513/27

q = -19

joja [24]3 years ago

6 0

Answer:

-19

Step-by-step explanation:

27x-19=-513

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2 years ago

Urpi wants to buy towels online. There are two stores with the kind of towel she wants. The first store charges $20 per towel, a

Kamila [148]

Answer:

1 A the first store.

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4 0

3 years ago

Read 2 more answers

Given: KLMN is a trapezoid, m∠N=m∠KML, FD=8, LM KN = 3 5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 5 Find: KM

denis23 [38]

Answer:

The length of side KM is $\sqrt{109}$ units.

Step-by-step explanation:

Given information: KLMN is a trapezoid, ∠N= ∠KML, FD=8, LM:KN=3:5, F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, $ME=3\sqrt{5}$ .

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is $3\sqrt{5}$ .

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since LM:KN=3:5, therefore LM is 3x and KN is 5x.

$\frac{3x+5x}{2}=8$

$\frac{8x}{2}=8$

$x=2$

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

$KN=KA+AE+EN$

$10=6+2(EN)$ (KA=EN, isosceles trapezoid)

$EN=2$

$KE=KN-EN=10-2=8$

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

$Hypotenuse^2=base^2+perpendicular^2$

$(KM)^2=(KE)^2+(ME)^2$

$(KM)^2=(8)^2+(3\sqrt{5})^2$

$KM^2=64+9(5)$

$KM=\sqrt{109}$

Therefore the length of side KM is $\sqrt{109}$ units.

8 0

3 years ago

Read 2 more answers

S= 2LW + 2LH + 2WH<br> solve for W

Darina [25.2K]

Rewrite the equation as

2lw+2lh+2wh=a.2lw+2lh+2wh=a

Subtract

2lh

from both sides of the equation.

2lw+2wh=a−2lh

Factor

2w out of 2lw+2wh.

2w(|+h)=w−2lh

Divide each term by

2(l+h)

and simplify.

.w=a−2lh2(l+h)

4 0

2 years ago