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2 years ago

Helppp pleaseeee xxxxx

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

7 0

Answer:

$h = 3\sqrt{3}$

$c = 4\sqrt{2}$

Step-by-step explanation:

✔️Finding h using trigonometric ratio:

Reference angle = 60°

Opposite = h

Adjacent = 3

Thus:

$tan(60) = \frac{h}{3}$

$\sqrt{3} = \frac{h}{3}$ (tan 60 = √3)

Multiply both sides by 3

$3\sqrt{3} = h$

$h = 3\sqrt{3}$

✔️Finding c using trigonometric ratio:

Reference angle = 45°

Hypotenuse = 8

Adjacent = c

Thus:

$cos(45) = \frac{c}{8}$

$\frac{\sqrt{2}}{2} = \frac{c}{8}$ (cos 45 = √2/2)

Multiply both sides by 8

$\frac{\sqrt{2}}{2} \times 8 = c$

$\sqrt{2} \times 4 = c$

$c = 4\sqrt{2}$

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Hey plsss help meeeeee

nalin [4]

Answer:

The first, third, and fourth answer choices represent a function.

Step-by-step explanation:

A relation is a relationship between sets of values. The two quantities that are being related to each other are the input (x-variable) and the output (y-variable). But relations in general aren't always a good way to relate between x and y.

Say that I have situation where I want to give <em>x </em>dollars to the cashier so he can change them to <em>y</em> quarters. Here is a "example" of the relation:

Dollars (x) | Quarters (y)

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0 | 0

1 | 4

2 | 8

2 | 12

Do you see something wrong here? Yes! We all know that you can't exchange 2 dollars for 12 quarters. You can only exchange 2 dollars for 8 quarters and only 8 quarters. This is a general reason why we don't rely on general relations for real-life situations. One x-variable does not exactly map to one and only one y-variable.

However, a relation that can map one x-variable to one and only one y-variable is known as a function. Let's make the above example an actual function to prove a point:

Dollars (x) | Quarters (y)

----------------------------------

0 | 0

1 | 4

2 | 8

3 | 12

Now, the 3 dollars make 12 quarters as it should. This is how a function should look like.

There are two ways to check if a relation is a function. On a relation, table, or a set of ordered pairs, you have to make sure there is no "x-variable" that repeats. All x-values of a relation have to be unique in order to be a function. On a graph, you can also perform the Vertical Line Test. If you draw vertical lines over a relation and if the lines cross only once, then it is a function. If not, it fails the Vertical Line Test.

So to answer you're question, the first, third, and fourth choices are functions because they all have unique x-variables. The second choice is not a function because it fails the Vertical Line Test.

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2 years ago

Please answer this question !! Thank u tons !! Will give brainliest !!

Anastaziya [24]

Answer: D

Step-by-step explanation:

The key to finding the line perpendicular to the one given is teh slope. The slope is the opposite reciprocal of the original line.

m=3

perpendicular m=-1/3

Now that we know the slope, we can see which of our answer choices have -1/3 as the slope. We can see D is the only option that has -1/3 for slope.

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Answer:

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Answer:

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Step-by-step explanation:

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Delicious77 [7]

Answer:

$f(x)=-a(x+2)(2x-1)(x-3)$ where a>0.

To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.

Step-by-step explanation:

The real zeros are the result of setting each factor of the polynomial to zero. By reversing this process, we find:

zero -2 is factor (x+2)

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zero 3 is factor (x-3)

We write them together with an unknown leading coefficient a which is negative so -a.

$f(x)=-a(x+2)(2x-1)(x-3)$ where a>0

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A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.

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