Question

A teacher's age is 6 years greater than 2 times a student's age. A principal's age is 10 years greater than 3 times

Answer 1

Answer:

b. x + 4

Solution:

Student's age = x

Teacher's age = 6 + 2x

Principal's age = 10 + 3x

Difference in the age of the teacher and principal

(10 + 3x) - (6 + 2x)

= 10 + 3x - 6 - 2x

= (10 - 6) + (3x - 2x)

= 4 + x