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andreev551 [17]

3 years ago

10

A power line stretches from the top of a building to the ground. The power line is 100ft. long and the building is 50 ft. tall.

What is the horizontal distance from the end of the power line to the building?

1 answer:

Nutka1998 [239]3 years ago

6 0

Answer:

86.6 ft.

Step-by-step explanation:

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Jane has 6/7 of a yard of ribbon. She uses 3/4 of a yard to trim an ornament. how much ribbon is left?

Degger [83]

Answer:

2/28

Step-by-step explanation:

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3 years ago

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74-25=59 a84+25=109 b59+25=84 c84+59=143

wel

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Partial product of 8.6x9.2

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You buy a new laptop for $300$300. The sales tax is 6%6%. What is the total cost for the laptop including the sales tax?

cricket20 [7]

Answer:

Cost Including tax would be $318

Step-by-step explanation:

Given:

Price of laptop = $300

Sales tax = 6% of price

To Find:

Cost with tax = ?

Solution:

Cost with tax = Price of laptop + Value of tax

We have to find the value of tax

Value of tax = 6% of Price

putting the value

Value of tax = 6 % * $300

$=\frac{6}{100}*300$

= $18

Now Cost with tax = Price of laptop + Value of tax

Putting in the value

Cost with tax = 300 + 18

= $318

So Cost Including tax would be $318

6 0

3 years ago

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago