Answer:
The answer is B: The area of the new rectangle is double it's original size
y^ ⁻⁹/⁴ * z^⁽⁻³⁾
Step-by-step explanation:
(Y^3 z^4)^(-3/4) = (y^3)^(-3/4) * (z^4)^(-3/4)
= y^3* ⁽⁻³/⁴⁾ * z^4 *⁽⁻³/⁴⁾
=y^ ⁻⁹/⁴ * z^⁽⁻³⁾
hi
$39284
formula is,
CA=p (1+r÷200)^2t
and inner radius 
![\displaystyle V = \int_0^1 \pi\Big[ \left( 2 - x^2 \right)^2 - \left( 2 - \sqrt{x}\right)^2\Big] dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V%20%3D%20%5Cint_0%5E1%20%5Cpi%5CBig%5B%20%5Cleft%28%202%20-%20x%5E2%20%5Cright%29%5E2%20-%20%5Cleft%28%202%20-%20%5Csqrt%7Bx%7D%5Cright%29%5E2%5CBig%5D%20dx)
