The true question should be like this:
<span>What is the center and radius of the following circle: x^2 + (y _ 6)^2 = 50,
circle quation formula is (x-a)^2 + (y-b)^2 = R², so by identifying each term, we find </span>(x-a)^2=x^2 = (x-0)^2, (y-b)^2= (y _ 6)^2, R² = 50, implies R =5sqrt(2),
it is easy to identify that the center is (a,b)= (0, 6)
the radius is R =5sqrt(2),
Answer:
i think we need more context to this answer. I’d love to help no need to retype. You can just message me for help :)
Step-by-step explanation:
Answer:
- x² - 8x + 12
- x³ + 2x² - 15x - 36
- x³ -2x² - 15x
Step-by-step explanation:
#1) Find the polynomial with roots at 2 and 6
-
(x -2)(x - 6) = x² - 8x + 12
#2) Find the polynomial with a double root at -3 and another root at 4
-
(x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36
#3) Find the polynomial with roots 0, -3 and 5
- (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x
Answer:
Formula for area of a circle;
<u>A = πr^2</u>
where pi is 3.14 in this case, and r is the radius squared
Plug in the actual values;
A = 3.14 x 11^2
A = 3.14 x 121
A = 379.94 square feet
Answer:
0.9
Step-by-step explanation:
10% is equal to 0.1
The probability of having defective parts in a pile of parts is 0.1
Before the process is stopped, 1 part has to be defective.
In a pile of 9 parts, the probability that a part is defective 0.1 of 9, which is = 0.9 hence, approximately one (1) part will be defective in a pile of 9 parts and the process will be stopped.
Since there was no defective part among the first 6 parts, P(d) was 0
That is, probability of a defective part was zero.
