Y-3=-2(x-5)
y-3=-2x+10
y=-2x+13
hope this helps :)
Answer:
Step-by-step explanation:
A.0.4 is by the left side up to 0 where they’re is no point
Given
Expenditures at Manager's Store; expenditures at Competitor's Store.
Find
a) average spent at each store
b) which store is better represented by the mean value
c) an explanation for the answer in ≥ 2 sentences
Solution
a) The sum of expenditures divided by the number of expenditures (15) is ...
... average for Manager's Store: $37.60
... average for Competitor's Store: $48.53
b) The expenditures at Manager's Store are well-represented by the mean (average).
c) The range of expenditures at Competitor's Store is significantly higher than at Manager's store, so a single number such as mean or median does not represent the data well. The expenditures at Manager's store are more compactly grouped around the mean and median, which are closer together, so the mean is a good representation of Manager's Store expenditures overall.
It can be up to 20 feet taller so add 20
To the width:
88 2/3 + 20 = 108 2/3
Divide total height by the height of one story:
108 2/3 / 15 = 7.24
The building can have 7 stories.
b. 7 x 15 = 105 total feet
108 2/3 -105 = 3 2/3 feet below the restrictions
Answer:
a) 
b) 
c)


Step-by-step explanation:
a)
We know that Revenue is our total income and cost is our total cost. Thus, profit is what's left after cost is subtracted from Income (revenue). Thus, we can say:
P(x) = R(x) - C(x)
Finding Profit Function (P(x)):

This is the profit function.
b)
The marginal profit is the profit earned when ONE ADDITIONAL UNIT of the product is sold. This is basically the rate of change of profit per unit. We find this by finding the DERIVATIVE of the Profit Function.
Remember the power rule for differentiation shown below:

Now, we differentiate the profit function to get the marginal profit function (P'):

This is the marginal profit function , P'.
c)
We need to find P'(4000) and P'(9500). So we basically put "4000" and "9500" in the marginal profit function's "x". The value is shown below:

and
