Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
the height of the trapezoid of 5, i think.
my work:
i used this formula: 2 x a + b / A
so, you plug in what you know.
2 x 8+6 / 35 = 5
Answer:
12
Step-by-step explanation:
if you find it difficult you can always write is down as a piece of side working
-14
-13
-12
-11
-10
-9
-8
-7
-6
-5
-4
-3
Answer:
The Distributive Property.
Step-by-step explanation:
4(x - 1) = 12
When distributing out the 4, it must go to all the terms within the brackets like this:
4x - 4 = 12.
4x = 16
x = 4.
B because if you take it it would be b
