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Fofino [41]
3 years ago
11

Giải pt sin(x^2-4x)=0

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0

Answer:

x=0,2half1?(I'm

not sure)

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In the cafeteria, 100 milk cartons were put out for breakfast. At the end of breakfast, 27 remained. 1.What is the ratio of milk
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<span>1. The r</span>atio of milk cartons taken to total milk cartons,
100 - 27 = 73 were taken
73/100 is the ratio of milk cartons taken to total milk cartons

2. The ratio of milk cartons remaining to milk cartons taken
27 / 73 is the ratio of milk cartons remaining to milk cartons taken
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PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points
MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

\\ \sf\longmapsto x^2+3x-70(4x-12)

\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840

\\ \sf\longmapsto -8x^2+48x+560

Now

\\ \sf\longmapsto (f.g)(3)

\\ \sf\longmapsto -8(3)^2+48(3)+560

\\ \sf\longmapsto -72+144+560

\\ \sf\longmapsto 72+560

\\ \sf\longmapsto 632

Part-B:-

\\ \sf\longmapsto f(3)

\\ \sf\longmapsto (3)^2+3(3)-70

\\ \sf\longmapsto 9+9-70

\\ \sf\longmapsto 18-70

\\ \sf\longmapsto -52

Now

\\ \sf\longmapsto g(f(3))

\\ \sf\longmapsto g(-52)

\\ \sf\longmapsto 4(-52-3)

\\ \sf\longmapsto 4(-55)

\\ \sf\longmapsto -220

Part:-C

\\ \sf\longmapsto g(-2)

\\ \sf\longmapsto 4(-2-3)

\\ \sf\longmapsto 4(-5)

\\ \sf\longmapsto -20

Now

\\ \sf\longmapsto f(g(-2))

\\ \sf\longmapsto f(-20)

\\ \sf\longmapsto (-20)^2+3(-20)-70

\\ \sf\longmapsto 400-60-70

\\ \sf\longmapsto 400-130

\\ \sf\longmapsto 270

Part-D:-

  • g×f=f×g

\\ \sf\longmapsto (g.f)(-2)

\\ \sf\longmapsto -8(-2)^2+48(-2)+560

\\ \sf\longmapsto 32-96+560

\\ \sf\longmapsto -64+560

\\ \sf\longmapsto 496

6 0
2 years ago
Can someone help me with this<br> 2x+4y+3z=6<br> x-2y+z=-5<br> -x-3y-2z=-7<br> solve for x,y,z
Flauer [41]

Answer:

x = -7 2/3, y = 1 1/3 and z = 5 1/3.

Step-by-step explanation:

2x+4y+3z=6    .....  1

x-2y+z=-5        ...... 2

-x-3y-2z=-7      .......3

Add equations 2 and 3 to eliminate x:

-5y - z = -12   .....4

Multiply equation 2 by - 2:

-2x + 4y  - 2z = 10

Add this to equation 1:

8y + z = 16   ........ 5

Now add equation 4 to equation 5:

3y = 4

y = 4/3 = 1 1/3.

Now find z by substituting for y in equation 4:

-5(4/3) - z = -12

z = 12 - 20/3

z = 36/3 - 20/3 = 16/3 = 5 1/3.

Finally, we find x by substituting for y and z in equation 1:

2x + 4*4/3 + 3*16/3 = 6

2x = 6 - 16/3 - 16

2x =  18/3 - 16/3 - 48/3 = -46/3

x = 23/3 =  7 2/3.

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3 years ago
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