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3 years ago

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Which situation could be represented by equation y=25/2x +10 ?

1 answer:

Alisiya [41]3 years ago

8 0

Hope this helps you:)

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Need help! Please hurry!!! Only have one person answer though!

Olegator [25]

Answer:

-7(a + 2b + 4)

Step-by-step explanation:

-7a - 14b - 28

⇒ -7(a + 2b + 4)

6 0

2 years ago

Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?

Mademuasel [1]

Answer:- a.The given expression is equivalent to $\frac{x^{10}y^{14}}{729}$

Given expression:- $[\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}$

$=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}$

$=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}$

$=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}$

$=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}$

$=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}$

Thus a. is the right answer.

6 0

3 years ago

Read 2 more answers

. In the formula p = kt, find t when k = 36 and p = 144.

lisov135 [29]

Answer:

t = 4

Step-by-step explanation:

p = kt

144 = 36t

t = 144/36

t = 4

7 0

2 years ago

Read 2 more answers

Karim's dog weighs 1.5 pounds less than double the weight to Frank's dog. Karim's dog weighs 15 pounds. Which equation and solut

Radda [10]

1. Because

info given:
Karim's dog = 15 pounds
Frank dog = 2x more pounds than Karim's dog + 1.5 pounds

(Karim) Equation 1: 15 = Frank
(Frank) Equation 2: 2w + 1.5

joining equation 1 and 2

15 = 2w + 1.5

Solve

15 - 1.5 = 2w
13.5 = 2w ÷ 2
w = 6.75

8 0

3 years ago

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 98% confidence inter

frosja888 [35]

Answer:

The minimum sample size required to create the specified confidence interval is 1024.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.327$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.08, \sigma = \sqrt{1.21} = 1.1$ .

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.08 = 2.327*\frac{1.1}{\sqrt{n}}$

$0.08\sqrt{n} = 2.327*1.1$

$\sqrt{n} = \frac{2.327*1.1}{0.08}$

$(\sqrt{n})^{2} = (\frac{2.327*1.1}{0.08})^{2}$

$n = 1024$

The minimum sample size required to create the specified confidence interval is 1024.

3 0

3 years ago