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s2008m [1.1K]
3 years ago
11

Help me please! It’s timed

Mathematics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

x=36.08

Step-by-step explanation:

Given: From the given triangle DEF, ∠E=90^{0}

DF=55

and DE= x

To find the value of x

According to trigonometry rule,

\frac{x}{55} =cos49^{0} \\x=55(cos 49^{0} )\\x=55(0.656)\\x=36.08

Therefore, the value of x will be 36.08

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Astronomers were trying to find the weight of six planets - Mars, Venus, Pluto, Jupiter, Mercury, and Saturn. The number of planets lighter than Mars was equal to the number of planets heavier than Venus. Saturn was heavier than Mars and Mercury were heavier than Pluto. Venus was lighter than Mars. Saturn was not the heaviest planet.

Step-by-step explanation:

7 0
3 years ago
Determine the zero of F(x)=x^2+3x-5
IgorLugansk [536]

Answer:

The answer to your question is:

Step-by-step explanation:

                                             x² + 3x - 5

                                    x² + 3x + (3/2)² = 5 + (3/2)²

                                         (x + 3/2)² = 5 + 9/4

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                                          (x + 3/2)² = 29/4

                                          x + 3/2 = ±√29 / 2

                                     

x 1 = -3/2 + √29/2                               x2 = -3/2 - √29/2

x1 = 1.19                                                x2 = -4.19

3 0
3 years ago
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Answer:

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Plutonium-240 decays according to the function where Q represents the quantity remaining after t years and k is the decay consta
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time = ln (5/6) / -.00011
time = -.018232155683 / -.00011
time = <span> <span> <span> 165.7468698455 </span> </span> </span>
time = <span> <span> <span> 165.75 years

</span></span></span>

7 0
3 years ago
Read 2 more answers
Sarah borrowed some money from her father at a simple interest rate of 5.5% to pay for her college tuition. At the end of the ye
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\bf ~~~~~~ \textit{Simple Interest Earned Amount}&#10;\\\\&#10;A=P(1+rt)\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$2555\\&#10;P=\textit{original amount deposited}\\&#10;r=rate\to 5.5\%\to \frac{5.5}{100}\to &0.055\\&#10;t=years\to &1&#10;\end{cases}&#10;\\\\\\&#10;2555=P[1+(0.055)(1)]\implies \cfrac{2555}{1+(0.055)(1)}=P&#10;\\\\\\&#10;\cfrac{2555}{1.055}=P\implies 2421.800947867 \approx P
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3 years ago
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