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3 years ago

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Three tanks are capable of holding 361,841, and 901 of the greatest vessel winch can be used to fill each one of them on exact n

umber of time

1 answer:

daser333 [38]3 years ago

6 0

Answer:

Tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

Step-by-step explanation:

Three tanks are capable of holding $361,841,901$

To find which tank can be used to fill each one of them an exact number of time, find $HCF(361,841,901)$

$361=19^2\\841=29^2\\901=17(53)$

Therefore,

$HCF(361,841,901)=1$

So, tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

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Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

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$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

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$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

$\frac{dV}{dt} =-1.396in^3/min$

The volume is decreasing at the rate of 1.396 cubic inches per minute

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Answer: There are 5 candies of first type and 4 candies of second type.

Step-by-step explanation:

Since we have given that

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