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Juli2301 [7.4K]
3 years ago
15

1.

Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

-40

20

20

20

Step-by-step explanation:

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I need help solving this problem with proofs if at all possible
k0ka [10]

I don't really like these algebra problems which pretend to be geometry.

The bisector makes two equal angles, so

x/2 + 17 = x - 33

50 = (1/2) x

x = 100

That means ABC = 100/2 + 17 = 67 degrees

CBD = 100 - 33 = 67 degrees, equal so that checks

We're asked for ABC which is 67 + 67 = 134 degrees

Answer: 134°

4 0
3 years ago
Read 2 more answers
3.
Vedmedyk [2.9K]

9514 1404 393

Answer:

  -25 dollars per month

Step-by-step explanation:

It is convenient to compute the rate of change using points where the graph crosses grid intersections. A couple of these are ...

  (months, dollars) = (1, 675)  and  (4, 600)

Using the slope formula, we have ...

  m = (y2 -y1)/(x2 -x1)

  m = (600 -675)/(4 -1) = -75/3 = -25 . . . . . dollars/month

8 0
3 years ago
If A+B= 45° then prove that: tanA+ tanB+ tanA. tanB​
Iteru [2.4K]

Answer:

See Explanation

Step-by-step explanation:

A+B= 45 \degree \\  \\ assuming  \:  \tan \: on \: both \: sides \\  \\\implies \: \tan( A+B)=  \tan 45 \degree \\  \\  \implies \: \tan( A+B)=  1 \:  \: \\  (  \because \: \tan 45 \degree = 1) \\  \\ \implies \:  \frac{\tan \: A +\tan \: B }{1 - \tan \: A .\tan \: B }  = 1 \\  \\ \implies \: \tan \: A +\tan \: B = 1 - \tan \: A .\tan \: B \\  \\ \purple{ \implies }\:  \orange{ \bold{\tan \: A +\tan \: B  + \tan \: A .\tan \: B= 1 }} \\  \\ thus \: proved

8 0
2 years ago
Amy walks from point B to point C along the segment BC. Fraser walks from point O to point A along the segment OA. Which stateme
torisob [31]
Based on the graph, point O is the center of the circle. 
Segment BC is a chord of the circle that passes through point O, it is a diameter.
Segment OA is a radius of the circle.

The correct statement for this problem is:

<span>Amy walks a distance equal to the diameter, and Fraser walks a distance equal to the radius of the lawn.</span>
3 0
3 years ago
A college student completed some courses worth 3 credits and some courses worth 4 credits. The student earned a total of 59 cred
DedPeter [7]

Answer:

They completed 13, 3 credit classes

Step-by-step explanation:

1. Make 2 formulas. In this case: x+y=18

and 3x+4y=59

2. Then multiply x+y=18 by 3 and subtract the two equations.

Find y which is 5 and input into the equations. Then find your answer.

5 0
3 years ago
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